Waverly is a census-designated place in Polk County, Florida, United States. The population was 1,927 at the 2000 census. It is part of the Lakeland?Winter Haven Metropolitan Statistical Area.Waverly is located at 2758?4?N 8137?19?W? / ?27.96778N 81.62194W? / 27.96778; -81.62194.According to the United States Census Bureau, the CDP has a total area of 3.6 square miles, of which 3.5 square miles is land and 0.04 square miles is water.As of the census of 2000, there were 1,927 people, 864 households, and 603 families residing in the CDP. The population density was 543.8 people per square mile. There were 1,178 housing units at an average density of 332.4/sqmi. The racial makeup of the CDP was 69.64% White, 25.53% African American, 0.16% Native American, 0.16% Asian, 0.26% Pacific Islander, 3.06% from other races, and 1.19% from two or more races. Hispanic or Latino of any race were 4.51% of the population.There were 864 households out of which 15.